v = \(\sqrt{1960}\)m/s = 44.2 m/s. If the mass of a body is 9.8 kg on the earth, what would be its mass on the moon? Two planets of radii R 1 and R 2 have the same density. Then weight becomes Wn = mG \(\frac{4 M}{\left(\frac{R}{2}\right)^{2}}\) = (16 m G) \(\frac{M}{R^{2}}\) = 16 × W0 F = mg …(2) The standard kilogram is the mass of a block of a platinum alloy kept at the international bureau of weights and measures near Paris in France. Answer: Answer: No. Free PDF Download - Best collection of CBSE topper Notes, Important Questions, Sample papers and NCERT Solutions for CBSE Class 9 Physics Gravitation. On what factors does that force depend? The mass of the Earth M is 5.98 x 1024 kg and the radius of the Earth R is 6.38 x 106 m. (3 marks) Answer The universal law of gravitation states that every object in the universe attracts every other object with a force called the gravitational force.The force acting between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. Will this ratio remain the same if (i) one of the objects is hollow and the other one is solid; and (ii) both of them are hollow, size remaining the same in each case? Define acceleration due to gravity. Question Answers, Page 134. Thus, the packets will remain in air for longer time interval, when it is dropped at the equator. OTP has been sent to your mobile number and is valid for one hour Answer: These questions are quite useful to prepare the objective type questions for … Why does formation of tides takes place in sea or ocean? Yes, fluids have weight. As u = 0, h1 = \(\frac{1}{2} g t_{1}^{2}\) For the second stone, Question 9. So, acceleration = \(\frac{\text { Force }}{\text { Mass }}=\frac{20}{1}\) = 20 m/s2, Question 3. Question 13. Answer: Given, Mass of the Sun, M = 2 x 10 30 kg And Radius of the earth, Re = 6.4 × 106 m. Question 7. Answer: Mass of the earth, Me = 6 × 1024 kg Free Question Bank for 11th Class Physics Gravitation Gravitation Conceptual Problems or, v = \(\sqrt{800}\) Here, if the masses mx and m2 of the two bodies are of 1 kg and the distance (r) between them is 1 m, then putting m1 = 1 kg, m2 = 1 kg and r = 1 m in the above formula, we get State the universal law of gravitation. Page No: 134. (e) What is the ball’s acceleration at point A? Gravitation is the force of attraction between any two bodies while gravity refers to attraction between any body and the earth. Initial velocity, u = 0 1. i.e., weight will increase by 10%. t1 = \(\frac{u}{g}\) …(1) Question 5. Yes. Answer: According to Newton’s third law of … Practice questions The gravitational force between […] A stone dropped from the roof of a building takes 4s to reach the ground. The weight of the body on the moon is about one-sixth of its weight on the earth. u = 0 + gt2 Answer: Initial speed, u = 0.5 m/s (G = 6.67 × 1011 Nm2kg-2) i.e., the second stone was thrown downward with a speed of 12.1 ms-1. “Every body in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.” Let us consider two bodies A and B of masses m1 and m2 which are separated by a distance r. Then the force of gravitation (F) acting on the two bodies is given by Isaac Newton. ∴ For the second stone, Now, mass of the earth, Me = 6 × 1024 kg Is weight a force? (3) Question 2. Answered by Expert ICSE IX Physics Upthrust in Fluids, Archimedes' Principle and Floatation. At the equator. (b) time of fall of the body? ∴ W = \(\frac{G M m}{r^{2}}\) mass of the moon, Mm = 7.4 × 1022 kg Question 1. Weight is the force of gravity acting on the body. Question 10. [NCERT Exemplar] or t = \(\frac{0.5}{9.8}\) = 0.05 s. Question 11. Question 21. Weight of an object is directly proportional to the mass of the earth and inversely proportional to the square of the radius of the earth, i.e., Prove that if a body is thrown vertically upward, the time of ascent is equal to the time of descent. \(\frac{W_{m}}{W_{e}}=\frac{M_{m}}{M_{e}} \times \frac{R_{e}^{2}}{R_{m}^{2}}\) …. Suppose the radius of the earth becomes twice of its present radius without any change in its mass, what will happen to your weight? Thus, equation (3) becomes, For both the stones radius of the earth, Re = 6400 km Question 10. % Variation in the weight of a body = % Change in g = 0.7%. Our online gravitation trivia quizzes can be adapted to suit your requirements for taking some of the top gravitation quizzes. (ii) Putting the values in the formula v = u + gt Answer: ⇒ Time of ascent = Time of descent. This is because acceleration due to gravity is independent of the mass of the falling body. A ball is thrown up with a speed of 0.5 m/s. Combining (1) and (2), we get ∴ v = u Find the position of that point. Answer: If the small and big stones are dropped from the roof of a house simultaneously, they will reach the ground at the same time. Question 3. State the universal law of gravitation. Answer: From (1) and (2), we get t1 = t2 ⇒ t = \(\sqrt{10}\) = 3.16 s Molecules in air in the atmosphere are attracted by gravitational force of the earth. On the moon’s surface, the acceleration due to gravity is 1.67 ms-2. Answer: Answer: But we know, acceleration ∝ 1/m. Q.17 Does the gravitational force same for two objects inside and outside the water? = 0 – (0.5)2 = 2 × (-9.8) × h h2 = \(\frac{1}{2} g t_{2}^{2}\), v2 = 2gs = 2 × 9.8 × 100 = 1960 Then what will happen to your weight? Why does a body orbiting in space possess zero weight with respect to a spaceship? Does the apple also attract the earth? Calculate its speed after 2 s. Also find the speed with which the stone strikes the ground. Question 17. G = F FQ = \(\frac{G \times M_{e} \times m_{2}}{R^{2}}\) ……. Asked by Umesh 1st December 2017 9:49 AM . F ∝ m,1m2 and F ∝ \(\frac{1}{r^{2}}\) [NCERT Exemplar] Let P and Q be the two bodies, Suppose that the radius of the earth becomes twice of its original radius without any change in its mass. Question 7. Calculate the height of the building. Answer. Question 7. The astronaut and the spaceship are orbiting with same acceleration hence, the body does not exert any force on the sides of the spaceship. = M + \(\frac{10}{100}\)M = M + \(\frac{M}{10}\) = \(\frac{11M}{10}\) = 1.1 M Answer: New weight becomes 1.1 times. Question 9. Yes. Why? Assume that g = 10 m/s2 and that there is no air resistance. Thus a big stone will fall with the same acceleration as a small stone. In a hypothetical case, if the diameter of the earth becomes half of its present value and its mass becomes four times of its present value, then how would the weight of any object on the surface of the earth be affected? v = 0 + gt2 Does the apple also attract the earth? or D = \(\frac{g R^{2}}{G \frac{4}{3} \pi R^{3}}=\frac{3 g}{4 \pi G R}\), Question 6. And the mass of body Q=m2 Answer: Both C and D; [(Kg-m/Sec 2) = N] Q.19 Weight of free fall object is. When M changes to new mass M’ Answer: What would happen to your weight? Acceleration, g = – 9.8 m/s2 Weight, W = mg, m = \(\frac{W}{g}\), m = \(\frac{9.8}{9.8}\) = 1 kg Answer: Two objects of masses ml and m2 having the same size are dropped simultaneously from heights h1 and h2, respectively. […] When does an object show weightlessness? The huge collection of Questions and Answers for academic studies, CBSE school. This test will determine your knowledge of the subject. or – 0.25 = -19.6 h Question 18. where G is a constant known as universal gravitational constant. The acceleration due to gravity is more at the poles than at the equator. Who formulated the universal law of gravitation? A stone is dropped from the top of a 40 m high tower. Free Question Bank for NEET Physics Gravitation. (b) No. Q1. Answer: Explain why all of them do not fall into the earth just like an apple falling from a tree. It means that the force on the apple due to earth’s attraction is equal to that on the earth due to apple’s attraction. Question 1. State the universal law of gravitation. Both stones will take the same time to reach the ground because the two stones fall from the same height. (f) Acceleration = 10 ms-2 Very Short Answer Type Questions. New mass, M’=M + 10% of M F ∝ m1 × m2…(1) \(\frac{\iota_{1}}{t_{2}}=\sqrt{\frac{h_{1}}{h_{2}}}\) Question 16. (2) On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface while another stone is simultaneously dropped from the same height. [NCERT Exemplar] Answer: The weight will become 16 times. Zero. Answer: If the earth attracts two objects with equal force, can we say that their masses must be equal? Since, the two forces, i.e., Fp and FQ are equal, thus from (1) and (2), The mass of the Sun is 2 x 10 30 kg and that of the Earth is 6 x 10 24 kg. As the mass of the earth is very large as compared to that of the apple, the acceleration experienced by the earth will be so small that it will not be noticeable. Zero. Browse from thousands of Gravitation questions and answers (Q&A). This force depends on the product of the masses of the planet and sun and the distance between them. Get all questions and answers of Gravitation of MAHARASHTRA Class 10 Physics on TopperLearning. The two bricks like a single body, fall with the same speed to reach the ground at the same time in case of free fall. Answer: When body is at a distance V from centre of the earth then g = \(\frac{G M}{r^{2}}\). Justify your answer. Question 2. The moon will begin to move in a straight line in the direction in which it was moving at that instant because the circular motion of moon is due to centripetal force provided by the gravitational force of the earth. This will clear students doubts about any question and improve application skills while preparing for board exams. Define the standard kilogram. We know that F = \(\frac{G M m}{r^{2}}\) as weight of a body is the force with which a body is attracted towards the earth, (a) Downward where Me = mass of earth and Re = radius of earth. Free PDF Download - Best collection of CBSE topper Notes, Important Questions, Sample papers and NCERT Solutions for CBSE Class 9 Physics Gravitation. Yes. Thus, the gravitational constant G is numerically equal to the force of gravitation which exists between two bodies of unit masses kept at a unit distance from each other. Answer: TopperLearning’s Experts and Students has answered all of Gravitation of MAHARASHTRA Class 10 Physics questions in detail. Suppose the mass of the earth somehow increases by 10% without any change in its size. (i) Original weight = \(\frac{G M m}{r^{2}}\), where M is the mass of the earth. (i) We know v2 – u2 Here, s = 100 m, u = 0 Fill in the blanks : _____ of an object is the force of gravity acting on it.. Class 9 - Physics - Gravitation . Answer: Answer: u = 0 ms-1, h = 49 m, In case of free fall acceleration does not depend upon mass and size. The entire NCERT textbook questions have been solved by best teachers for you. Question 5. If the average distance between the Sun and the Earth is 1.5 x 10 11 m, calculate the force exerted by the Sun on the Earth and also by Earth on the Sun. If the radius of the earth becomes twice of its original radius, then i.e., First stone would take 3.16 s to reach the ground. Draw areal velocity versus time graph for mars. A: Yes B: No. ∴ v = 0 + (-10) × 2 = -20 ms-1 Gravitational force between moon and the earth keeps moon in uniform circular motion around the earth. Answer: W = \(\frac{G M m}{(2 r)^{2}}\) mg = \(G \frac{m M}{R^{2}}\) or g = \(\frac{G M}{R^{2}}\) …(3) Answer: How does the weight of an object vary with respect to mass and radius of the earth? [NCERT Exemplar] Answer: Solution: The universal law of gravitation states that every object in the universe attracts every other object with a force called the gravitational force. Answer: This law states that every body in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to square of distance between them. Answer: That is, for the second stone, t = (3.16 – 1)s = 2.16s 1. Balbharati solutions for Science and Technology Part 1 10th Standard SSC Maharashtra State Board chapter 1 (Gravitation) include all questions with solution and detail explanation. Give one example each of central force and non-central force. It is denoted by ‘g’. Question 3. Answer: ... plz answer this questions. (i) How high will it go before it begins to fall? How is gravitation different from gravity? Here are some practice questions that you can try. (b) At point B part1, Page 1 Question 7: Law of gravitation gives the gravitational force between (a) the earth and a point mass only (b) At which point is the bal 1 stationary? Find the percentage change in the weight of a body when it is taken from the equator to the poles. Suppose gravity of earth suddenly becomes zero, then which direction will the moon begin to move if no other celestial body affects it? (ii) How long will it take to reach that height? Zero. MCQs on CBSE Class 9 Science Chapter- Gravitation are provided here with answers. or h = \(\frac{0.25}{19.6}\) = 0.0127 m Question 14. Gravity itself is a natural phenomenon. MCQ quiz on Gravitation multiple choice questions and answers on gravitation MCQ questions quiz on gravitation objectives questions with answer test pdf. The earth attracts an apple. = \(\frac{G M m}{4 r^{2}}=\frac{W}{4}\) 0 = 0.5 – 9.8t , Difficult word of chapter the tale of melon city. The solved question papers from chapter 08 Gravitation have all type of questions may be asked in annual exams such as VSA very short answer type questions, SA short answer type questions, LA long answer type questions, VBA value based questions and HOTS higher order thinking skill based questions. [NCERT Exemplar] Answer: We know that G = 6.67 × 10-11 Nm2 kg-2 The gravitational force is responsible for providing the necessary centripetal force which allows the earth to move around the sun at the defined path or orbit. It is different at different places on the surface of the earth. A small value of G indicates that the force of gravitational attraction between two ordinary sized objects is a very weak force. Acceleration due to gravity is the acceleration acquired by a body due to the earth’s gravitational pull on it. As we know s = ut + \(\frac{1}{2}\) gt2 It will remain the same on the moon, i.e., 9.8 kg. These Gravitation Objective Questions with Answers are important for competitive exams like JEE, NEET, AIIMS, JIPMER etc. Take the Quiz and improve your overall Physics. As the body falls back to the earth with the same velocity it was thrown vertically upwards. Downward motion What will be its speed when it has fallen 100 m? The force (F) of gravitational attraction on a body of mass m due to earth of mass M and radius R is given by Kerala Plus One Physics Chapter Wise Questions and Answers Chapter 8 Gravitation Plus One Physics Gravitation One Mark Questions and Answers Question 1. Upward motion Question 2. 1. the mass of body P = m1 Give three differences between acceleration due to gravity (g) and universal gravitational constant (G). Answer: What keeps the moon in uniform circular motion around the earth? Ask your doubt of gravitation and get answer from subject experts and students on TopperLearning. Answer: Given m1 = 3 kg; m2 = 12 kg Calculate the value of acceleration due to gravity g using the relation between g and G. 6.7 × 10-11 Nm2 kg-2) everywhere in the universe. Answer: It occurs only when a body is in a state of free fall under the effect of gravity alone. Answer: (d) The quantity G is universal constant of nature. Practicing All Gravitation - IIT JEE Entrance Exam Questions and Answers in online helps you to improve your ability to attend the real time maths, chemistry, physics Entrance Exams. Question 19. Because the value of acceleration due to gravity (g) on the moon’s surface is nearly l/6th to that of the surface of the earth. So, the earth does not fall into the sun. If you are a student of class 9 who is using NCERT Textbook to study Science, then you must come across Chapter 10 Gravitation. NCERT Solutions for Class 6, 7, 8, 9, 10, 11 and 12, Extra Questions for Class 9 Science Chapter 10 Gravitation. Question 5. So, both the stones will reach the ground at the same time when dropped simultaneously. It is different at different places. Question 6. The tides in the sea formed by the rising and falling of water level in the sea are due to the gravitational force of attraction which the sun and the moon exert on the water surface in the sea. F = \(G \frac{m M}{R^{2}}\) …..(1) Question 1. Here, g = 1.67 ms-2, R = 1.74 × 106 m and G = 6.67 × 10-2 Nm2 kg-2, Question 2. For the first stone Both the bodies fall with the same acceleration towards the surface of the earth. v = u + gt2 Show that the weight of an object on the moon is \(\frac{1}{6}\) th of its weight on the earth. Suppose the mass of the moon is Mm and its radius is Rm. Question 8. When r changes to 2r, the new weight is given by Acceleration, a = g = 9.8 m/s2 The earth is acted upon by gravitation of sun, even though it does not fall into the sun. Professionals, Teachers, Students and Kids Trivia Quizzes to test your knowledge on the subject. Access Answers to NCERT Class 9 Science Chapter 10 – Gravitation ( All In text and Exercise Questions Solved) Exercise-10.1 Page: 134. For example, given the weight of, and distance between, two objects, you can calculate how large the force of gravity is between them. Become a part of our community of millions and ask any question that you do not find in our Gravitation Q&A library. Using physics, you can calculate the gravitational force that is exerted on one object by another object. Question 1. Question 1. 0 = u – gt1 Weightlessness is a state when an object does not weigh anything. \(\frac{G \times M e \times m_{1}}{R^{2}}=\frac{G \times M_{e} \times m_{2}}{R^{2}}\) Answer: [NCERT Exemplar] The entire NCERT textbook questions have been solved by best teachers for you. = \(20 \sqrt{2}\)ms-1, Question 6. or, v2 – 02 = 2(-10) × (-40) Answer: What will happen to the gravitational force between two bodies if the masses of one body is doubled? (i) As v = u + gt What is the source of centripetal force that a planet requires to revolve around the sun? (d) What is the ball’s acceleration at point C? They both hit the ground at the same time. Answer: Here, initial velocity, u = 0 Answer: ⇒ m1 = m2, Question 3. The time taken for a body is less if the acceleration due to gravity is more when the initial velocities and the distance travelled are the same. Question 4. Answer: The Following Section consists of Gravitation Questions on Physics. According to Newton’s third law of motion, action and reaction are equal and opposite. Answer: The accepted value of G is 6.67x 1CT-11 Nm 2 kg-2. Gravitation is the force of attraction that tends to draw together any two objects in the universe. QUESTION 6 (2002 EXAM) (a) Calculate the magnitude of the gravitational acceleration g at the Earth's surface, using Newton's second law and the law of universal gravitation. Answer: We know from Newton’s second law of motion that the force is the product of mass and acceleration. When hypothetically M becomes 4 M and R becomes \(\frac{R}{2}\). Question 12. Answer: Question 4. Register online for Science tuition on Vedantu.com to score more marks in your examination. Why does a body reach the ground quicker at poles than at the equator when dropped from the same height? A: 1 kg B: 9.8 kg C: 9.8 Kg-m/Sec 2 D: 9.8 N. Answer. Answer: Similarly, the force of attraction between the earth and the body Q is given by If a body of mass m is placed on the surface of moon, then weight of the body on the moon is Class 9 | Science | Chapter 10 |Gravitation| NCERT Solutions. Question 15. Mention any four phenomena that the universal law of gravitation was able to explain. The position of required point is at a distance of 4 m from mass of 3 kg. How does the force of attraction between the two bodies depend upon their masses and distance between them? Question 1. Question 1. Why? Height of the building, h = ? A: mass of the object × gravitational acceleration B: Zero We know that g = \(\frac{G M}{R^{2}}\) or M = \(\frac{g R^{2}}{G}\) (c) At point B Is the time taken by a body to rise to the highest point equal to the time taken to fall from the same height? Two bodies of masses 3 kg and 12 kg are placed at a distance 12 m. A third body of mass 0.5 kg is to be placed at such a point that the force acting on this body is zero. (Where Ve is the volume of the earth) (a) No Why is ‘G’ called the universal gravitational constant? and radius of the moon, Rm = 1740 km Answer: Q.18 What is the weight of a body of mass 1 kg? (c) At which point is the bal 1 at its maximum height? Question 4. ⇒ Average density of the earth, D = \(\frac{\text { Mass }}{\text { Volume }}=\frac{g R^{2}}{G \times V e}\) ans F ∝ \(\frac{1}{r^{2}}\) ..(2) ⇒ t2 = \(\frac{98}{9.8}\) = 10 Velocity-time graph for the ball’s motion is shown in figure. So, when dropped from the same height a body reaches the ground quicker at the poles than at the equator. t2 = u/g …(2) Original weight, W0 = mg = mG \(\frac{M}{R^{2}}\) (g) At point C, RD Sharma Class 11 Solutions Free PDF Download, NCERT Solutions for Class 12 Computer Science (Python), NCERT Solutions for Class 12 Computer Science (C++), NCERT Solutions for Class 12 Business Studies, NCERT Solutions for Class 12 Micro Economics, NCERT Solutions for Class 12 Macro Economics, NCERT Solutions for Class 12 Entrepreneurship, NCERT Solutions for Class 12 Political Science, NCERT Solutions for Class 11 Computer Science (Python), NCERT Solutions for Class 11 Business Studies, NCERT Solutions for Class 11 Entrepreneurship, NCERT Solutions for Class 11 Political Science, NCERT Solutions for Class 11 Indian Economic Development, NCERT Solutions for Class 10 Social Science, NCERT Solutions For Class 10 Hindi Sanchayan, NCERT Solutions For Class 10 Hindi Sparsh, NCERT Solutions For Class 10 Hindi Kshitiz, NCERT Solutions For Class 10 Hindi Kritika, NCERT Solutions for Class 10 Foundation of Information Technology, NCERT Solutions for Class 9 Social Science, NCERT Solutions for Class 9 Foundation of IT, PS Verma and VK Agarwal Biology Class 9 Solutions, NCERT Solutions for Class 10 Science Chapter 1, NCERT Solutions for Class 10 Science Chapter 2, Periodic Classification of Elements Class 10, NCERT Solutions for Class 10 Science Chapter 7, NCERT Solutions for Class 10 Science Chapter 8, NCERT Solutions for Class 10 Science Chapter 9, NCERT Solutions for Class 10 Science Chapter 10, NCERT Solutions for Class 10 Science Chapter 11, NCERT Solutions for Class 10 Science Chapter 12, NCERT Solutions for Class 10 Science Chapter 13, NCERT Solutions for Class 10 Science Chapter 14, NCERT Solutions for Class 10 Science Chapter 15, NCERT Solutions for Class 10 Science Chapter 16, CBSE Previous Year Question Papers Class 12, CBSE Previous Year Question Papers Class 10. 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